Math, asked by kothildangsawa, 5 hours ago

baichung father is 26 years younger than baichung grand father and 29 years older then baichung.the sum of the ages of all three is 135 years.what is the age of each one of them?​

Answers

Answered by manoj858
0

Step-by-step explanation:

Let Baichung's age be x years

Given that

Baichung's father is 29 years older than Baichung

Baichung's father age = (x + 29) years

Also,

Baichung's father is 26 years younger than Baichung's grandfather Age of Baichung's Father Age of Baichung's Grandfather - 26

Age of Baichung's Father + 26 Age of Baichung's Grandfather

Age of Baichung's Grandfather Age of Baichung's Father + 26

Age of Baichung's Grandfather = (x + 29) + 26

= (x + 55) years

Given,

Sum of all ages is 135 years

x + (x + 29) + (x + 55) = 135

3x+84 135

3x = 135 - 84

3x = 51

3x = 51

X =51/3

X = 17

Baichung's age = x = 17 years

Baichung's Father age = x + 29 17 +29= 46 years Baichung's Grandfather age = x + 55 17+ 55 =72 years

Answered by akulteju
0

Answer:

you should show me a answer

Similar questions