sin³θ + cos³θ/sinθ+cosθ = 1-sinθcosθ
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Answer:
Hey friend ur answer is in the pic
Step-by-step explanation:
Formulae used :
1) a³+b³ = ( a + b )( a² - ab + b² )
Identity used :
1) sin²x + cos²x = 1
( here x is actually theta ; just for simplicity I hav written x. )
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