Question

Balance the chemical equation
2
6 Ast
1 C + HNoz - H2CO3
2
Pt HN3
tung →
9 SB + w 3 -
+ Noz + H₂
H3PO4 + N2 + H2O
Hz As u + Noz + H2O
356 oy & Noot +120​

Answer 1

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No. of moles if Enzyme = Volume (city)× molarity= moles of Enzyme =6.022×10 2 3)

For one second

1 molecule of Enzyme ≡10

6

molecules of CO A

molecules of Enzyme ≡n molecule of COA

n=10 A

....... molecules of C02

For 1 hour = 3600 sec

No.of moleculy of CO 2

hydracted =3600×10 A

No. of moles of CO

hydracted = 3600×10 =3.6 mole

ml.ut of CO

2

=44

Let of Co

2

hydracted =3.6×44 gm

=158.4 gm

Four digit ans =(1584)