Question

Balance the chemical equation. with steps
$CO_2+H_2O \to C_6H_{12}O_6+O_2+H_2O$

Answer 1

Answer:

$\bold{6CO_2+7H_2O \to C_6H_{12}O_6+6O_2+H_2O}$

Explanation:

Always try to start with an element other than Hydrogen or Oxygen. In this case, we can start with Carbon. Since there are 6 Carbons on the right hand side of the arrow($\to$), we need 6 Carbons on the left hand side. $6 CO_2 + H_2O \to C_6H_{12}O_6 + O_2 + H_2O$.

Next, look at the Hydrogen: 2 on the left hand side and 14 on the right hand side. We need 14 on the left hand side: $6 CO_2 + 7 H_2O \to C_6H_{12}O_6 + O_2 + H_2O$

Now check the Oxygen: 19 on the left hand side and 9 on the right hand side. We need 19 on the right so we put in a coefficient of 6 in front of the $O_2$:

$6 CO_2 + 7 H_2O \to C_6H_{12}O_6 + 6 O_2 + H_2O$

Answer 2

$6CO_2+12H_2O\to C_6H_12_O_6+ 6O_2+6H_2O$

hope this helps

plz mark as brainliest answer