Chemistry, asked by geniusbro60, 1 year ago

balanced equation for copper carbonate decomposes to form copper oxide and carbon dioxide​

Answers

Answered by AmritanshuKeshri71
2
\huge\bf{\red{\mid{\overline{\underline{Answer}}}\mid}}

\bold{\small{\color{orange}{Using\:laws\:of\:conservation\:of\:mass}}}

The laws of conservation of mass states that the total number of atoms of different elements in reactants are equal to the total number of atoms in different elements in products during the chemical reaction.

\bold{\small{\color{green}{Balanced\:Chemical\:Equation:}}}

CuCO_3(s) --^{heat}--> CuO(s) + CO_2(g)

It is a decomposition reaction.

\bold{\small{\color{green}{Now\:see\:how\:to\:balance:}}}

a).Number of Copper atoms in left hand side is equal to the number of copper atoms in right hand side is 1.

b). Number of carbon atoms in left hand side is equal to the number of carbon atoms in right hand side is 1.

c). Number of oxygen atoms in left hand side is equal to the number of oxygen atoms in right hand side is 3.
Answered by nosumittiwari3
2

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Equation 1: 2CuCO3 (s) Cu2O (s) + 2CO2 (g) + O2 (g) 

Equation 2: CuCO3 (s) CuO (s) + CO2 (g)



The aim of this experiment is to prove which equationis correct.




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