Question

how can we balance barium carbonate decomposes to form barium oxide and carbon dioxide​

Answer 1

$\huge\bf{\blue{\mid{\overline{\underline{Answer}}}\mid}}$

$\bold{\small{\color{orange}{Using\:laws\:of\:conservation\:of\:mass}}}$

The laws of conservation of mass states that the total number of atoms of different elements in reactants are equal to the total number of atoms in different elements in products during the chemical reaction.

$\bold{\small{\color{green}{Balanced\:Chemical\:Equation:}}}$

$BaCO_3(s) --^{heat}--> BaO(s) + CO_2(g)$

It is a decomposition reaction.

$\bold{\small{\color{green}{Now\:see\:how\:to\:balance:}}}$

a).Number of Barium atoms in left hand side is equal to the number of barium atoms in right hand side is 1.

b). Number of carbon atoms in left hand side is equal to the number of carbon atoms in right hand side is 1.

c). Number of oxygen atoms in left hand side is equal to the number of oxygen atoms in right hand side is 3.

Answer 2

Hey mate here is your Ans ❤❤.....

It is already balanced...

see the attachment...