Question

Balanced equation for the reaction of iodine and sodium thiosulfate

Answer 1

Answer:

Sodium thiosulfate react with iodine ➡

2Na2S2O3 + I2 → Na2S4O6 + 2NaI

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Answer 2

Answer:

$\[{\mathbf{2N}}{{\mathbf{a}}_{\mathbf{2}}}{{\mathbf{S}}_{\mathbf{2}}}{{\mathbf{O}}_{\mathbf{3}}} + {{\mathbf{I}}_{\mathbf{2}}} \to {\mathbf{2NaI}} + {\mathbf{N}}{{\mathbf{a}}_{\mathbf{2}}}{{\mathbf{S}}_{\mathbf{4}}}{{\mathbf{O}}_{\mathbf{6}}}\]$

Explanation:

$\[{\mathbf{2N}}{{\mathbf{a}}_{\mathbf{2}}}{{\mathbf{S}}_{\mathbf{2}}}{{\mathbf{O}}_{\mathbf{3}}} + {{\mathbf{I}}_{\mathbf{2}}} \to {\mathbf{2NaI}} + {\mathbf{N}}{{\mathbf{a}}_{\mathbf{2}}}{{\mathbf{S}}_{\mathbf{4}}}{{\mathbf{O}}_{\mathbf{6}}}\]$

This reaction is involved in iodometric titration.

Sodium thiosulfate is a reducing agent and is usually used in redox titration, also known as iodometric titration. It is specially used for titrating iodine. Iodometric titration is generally used to determine the concentration of the oxidising agent in a solution. Iodine itself acts as an indicator in iodometric titration so we do not need any external indicator.