Question

ball of mass 10 g is initially moving with a velocity of 50 m sl. On applying a constant force on ball for 2.0 s, it acquires a velocity of 70 ms-1. Calculate: (i) the initial momentum of ball (ii) the final momentum of ball​?spam=10answer report?​

Answer 1

Answer:

Perfect Question:-

• Ball of mass 0.01 is initially moving with a velocity of 50 m sl.On applying a constant force on ball for 2.0s.It acquires a velocity of 70 ms^-1.

□To prove :-

1. Initial momentum.
2. Final momentum.

□Explanation :-

• $momentum \: is \: defined \: as \: the \: product \: of \: mass \: and \: velocity$
• $by \: mathematical \: expression \: we \: can \: write \: it \: as$
• $P= m.v$
• SI unit =Ns.

□Case (i):-

1. $initial \: momentum$

• $P = m \times u$
• $p = 0.01 \times 50$
• $p = 0.5Ns$

□Case (ii):-

1. $final \: momentum$

• $P=m \:times 20$
• $P=0.01 \:times 70$
• $P=0.7Ns$

♧Hope it helps u mate .

♧Thank you .

Answer 2

Answer:

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Step-by-step explanation:

$mass \: of \: ball \: (m) = 10.g = 0.01 \: kg\\ initial \: velocity \: (u) = 50.m/s \\ time \: taken \: (t) = 2.0 \: s= 2.s \\ so \: now \: using \\ initial \: momentum \: (p1) = m.u \\ = 0.01 \times 50 \\ = 0.5.kg \: m/s$

$now \: we \: know \: that \\ v = u + at \\ where \: a = 9.8 \: m/s {}^{2} \\ = 50 + (9.8 \times 2) \\ = 50 + 19.6 \\ = 69.6 \: m/s$

$so \: now \: using \\ final \: momentum \: (p2) = m.v \\ = 69.6 \times 0.01 \\ = 0.696 \: kg.m/s$

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