Question

Barium ions cn- and co+2 ions form ionic complex if that is the supposed to be 75% ionised in water with the van't hoff factor equal to 4 then the coordination number of cobalt + 2 ions in the complex can be

Answer 1

2 * atomic mass of ba, hydrogen, cobalt,copper

Answer 2

Given:

i = 4

Percentage of ionization (α) = 75 % = $\frac{3}{4}$

To find:

Coordination number of cobalt $2^+$ ions in the complex = ?

Solution:

$\alpha = \frac{i-1}{n-1}$

$\frac{3}{4} = \frac{4-1}{n-1}$

Upon cross multiplication and simplification, the value of n is obtained as 5.

Consider the charge on cobalt be 'x'

∴ Charge of anion = X - 2

Charge of counter ion = 2

∵ X-2+2 = n

X-2+2 = 5

X = 5

Conclusion:

Thus Coordination number of cobalt $2^+$ ions in the complex is 5.

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