Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the Ratio of areas of these triangles
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Area of 1st Triangle=½×base×height
½×9×5=45/2
Area of another Triangle=½×10×6
60/2=30
Ratio= area of 1st ∆/area of another ∆
= 45/2÷30
= 45/60
=3/4
3:4
½×9×5=45/2
Area of another Triangle=½×10×6
60/2=30
Ratio= area of 1st ∆/area of another ∆
= 45/2÷30
= 45/60
=3/4
3:4
Answered by
2
Heya !!!
Base of triangle = 9 units
And,
Height of triangle = 5 units
Area of triangle = 1/2 × ( B × H )
=> 1/2 × ( 9 × 5)
=> 45/2 units
Base of another triangle = 10 units
And,
Height of another triangle = 6 units
Area of another triangle = 1/2 × ( B × H )
=> 1/2 × ( 10 × 6)
=> 30 units
Ratio of the triangle = 45/2 : 30
=> 45/2 / 30
=> 45/2 × 1/30
=> 45/60
=> 9/60
=> 3:4
★ HOPE IT WILL HELP YOU ★
Base of triangle = 9 units
And,
Height of triangle = 5 units
Area of triangle = 1/2 × ( B × H )
=> 1/2 × ( 9 × 5)
=> 45/2 units
Base of another triangle = 10 units
And,
Height of another triangle = 6 units
Area of another triangle = 1/2 × ( B × H )
=> 1/2 × ( 10 × 6)
=> 30 units
Ratio of the triangle = 45/2 : 30
=> 45/2 / 30
=> 45/2 × 1/30
=> 45/60
=> 9/60
=> 3:4
★ HOPE IT WILL HELP YOU ★
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