Question

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH₃OH, CH₃CN.

Answer 1

Depending on the interaction based on electronegativities of the two atoms sharing electrons, there may be partial transfer of electron concentration from one atom to the other atom.

When the electronegativities are not equal in force , electrons are not shared equally and partial ionic charges develop.

The greater the electronegativity difference, the more ionic the bond results.

Bonds that are partly ionic are called polar covalent bonds.

Nonpolar covalent bonds, with equal sharing of the bond electrons, arise when the electronegativities of the two atoms are equal.

Normal  octane is a non polar liquid, Non polar compound always dissolve in non polar solvent very easily and cannot dissolve in Ionic substance.Cyclohexane and n-octane both are non-polar.

Hence, they mix easily.KCl is an ionic compound so KCI will not dissolve in n-octane.

CH3OH and CH3CN both are polar but CH3OH is more polar than CH3CN.

So it will less soluble as compare to CH3CN.We get.Cyclohexane: non-polarKCl  : ionic, CH3OH : polar covalent,CH3CN : weakly polar covalent.Hence the order of solubility will be KCI < CH3OH < CH3CN < Cyclohexane……..Answer

Answer 2

Hey !!

1) Cyclohexane and n-octane both are non-polar. Hence, they will mix completely in all proportions.

2) KCl is an ionic compound whereas n-octane is non-polar. Hence, KCl will not dissolve at all in n-octane.

3) CH₃OH and CH₃CN both are polar but CH₃CN is less polar than CH₃OH. As n-octane is non-polar CH₃CN will dissolve more than CH₃OH in n-octane.

Therefore, the order of solubility in n-octane will be KCl < CH₃ON < CH₃CN < Cyclohexane.

Hope it helps you !!