Question

BASIC LEVEL
1. A particle travels 24.6 kun in 30 minutes. Find the
speed of the particle in
2. A high-speed train travels at a speed of 200 km/h
If the train sets off from Station A at 12 24 and
reaches Station B at 14 12, find the distance
between the two stations, giving your answer in
metres
3. Express each of the following in km/h.
(a) 8.4 km min (b) 315 m/s
(d) 125 cm/s​

Answer 1

Answer:

1.49200m/s

Step-by-step explanation:

speed =distance(m)/time(s)

Answer 2

Step-by-step explanation:

Formulas for calculating distance =

D = Speed X Time

S = Distance

Time

T = Distance

Speed

Solution:

1. Correct Question

⭐A particle travels 24.6km in 30minutes find

the speed of particle in km/h.

Here we need to find out speed,

Given : A particle travels 24.6 km in 30 minutes.

To find : The speed of particle in km/h ?

$speed = \frac{distance}{time}$

Distance= 24.6 km

Time= 30 min

Covert into hours :

Minutes into hours

1 min = 1 hr.

60

30 min = 30 hr.

60

30 min = 0.5 hr

$speed = \frac{24.6}{0.5}$

$speed = 49.2 \: kmph$

: Speed is 49.2 km/hr.

2.

The distance between the two stations is 360 km

Solution:

Given that,A high speed train travels at a speed of 200km/h

Therefore,speed = 200 km/hr

The train sets off from station A at 12:24 and reaches at station B at 14:12

Therefore,Total time travelled = 12 : 24 to 13 : 24 + 13 : 24 to 14 : 12Total time travelled = 1 hour + 0.8 hour = 1.8 hour

The distance is given by formula:

distance= speed X time

Distance= 200 X 1.8

Distance = 360 km

Thus the distance between the two stations is 360 km.

3.

Express each of the following in km/h.(a) 8.4 km min (b) 315 m/s(d) 125 cm/s

For this question please refer to the attachments..

Hope it here you..