Question

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Answer 1

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Answer 2

Answer:

Angle ACB = 79°

Step-by-step explanation:

To find < BOC

It is given that, <AOC = 152

<AOB + <BOC = 360 - 152 = 208

<AOB : <BOC = 5: 3

<AOB= (5 x 208)/8 = 130°

<BOC = 208 - 130 = 78°

To find <ACB

Triangle AOC and triangle BOC are isosceles triangles.  

<OAC = <ACO = (180 - 152)/2 =28°

Similarly <OCB = <OBC =1/2 (180 - <BOC) = 1/2(180 - 78) = 51°

Therefore <ACB = <ACO + <OCB = 28 + 51 = 79°