Question

Bhaumik thought of a number whose
double is 45 greater than its half.​

Answer 1

Answer:

30

Step-by-step explanation:

Let the number be x.

Then, according to the question,

2x=45+1x/2

2x-1x/2=45

3x/2=45

3x=90

x=90/3

x=30

Therefore the number is 30.

I hope this helps... ☺☺

Answer 2

Answer :-

$\bf\huge\boxed{30}$

Explanation :-

Given :

• A number whose double is 45 greater than its half

To find :

The number

Solution :-

Let the number be x

According to question,

$= > 2x = 45 + \dfrac{x}{2}$

$= > 2x - \dfrac{x}{2} = 45$

$= > \dfrac{4x - x}{2} = 45$

$= > \dfrac{3x}{2} = 45$

$= > 3x = 90$

$= > x = \dfrac{90}{3}$

$= > x = 30$

Hence, the number Bhaumik thought was 30.

Verification :-

Putting the value of x

$= > 2 \times 30 = 45 + \dfrac{30}{2}$

$= > 60 = 45 + 15$

$= > 60 = 60$

Therefore, L.H.S = R.H.S

Hence, Proved.