Question

bi quadratic simplify it

(x+1)(x+2)(x+3)(x+4)-8​

Answer 1

x(x−1)(x+2)(x−3)+8=0

⇒(x 2  −x)(x  2  +(2−3)x+2×−3)+8=0

⇒(x  2 −x)(x  2  −x−6)+8=0

⇒x  4  −x  3  −6x  2  −x  3  +x  2  +6x+8=0

⇒x  4  −2x  3  −5x  2  +6x+8=0

Let f(x)=x  

4  −2x  3  −5x  2  +6x+8=0

Let x=−1⇒f(−1)=(−1)  

4  −2(−1)  3  −5(−1)  2  +6(−1)+8=0  

=1+2−5−6+8=0

∴x=−1 is one root of the above equation.

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Answer 2

Step-by-step explanation:

We kno w that

X⁴-(abc+bcd+cda+abd) X³ + (ab + bc+cd +ac +ad) x² -( a +b+c+d) +abcd

=x⁴-50x³ +31x² - 10x +24 -8

=x⁴-50x³ +31x² - 10x +16