Question

Find the three numbers in GP whose sup is 21 and whose product is 216

Answer 1

Answer:

the three number are 12 ,6 and 3 if we add then it becomes 21 and multiply then it become 216.

total number which have the sum of 21 and product of 216 = 3

then 216 ÷ 3 =72

therefore and the double of 3 is equal to 6 and then 72 divide 6=12

now 12+6+3=21

and 12×6×3=216.

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Answer 2

Answer:

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