Question

Block of mass m is pushed towards a movable wedge of mass m and height h with a velocity u. All surfaces are smooth. When the block collides with the wedge, the velocity of centre of mass of block-wedge system will be__

Answer 1

V (com) will be (Mass of block+mass of wedge)*v

Answer 2

Answer:

Explanation:

Vcm= mu + 0/m +nm = u/ 1 + n

1/2 mu^2 = 1/2 (M + nm) vcm^2 + mgh

u =[ 2gh (1 + 1/n)] ^1/2