Body cover a distance of 5 metre along a semicircular path the ratio of distance to displacement is
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Answer:
11:7 (Simplest form)
Explanation:
A/Q:-
Circumference of the semi-circle=5m
=>πr = 5m
=>22/7 × r =5m
=>r= 5÷22/7
=>r=5 × 7/22
=>r = 35/22
Distance covered =5m (given)
Therefore, Displacement = r+r
= 2r
=2×35/22
=35/11
The ratio of distance to Displacement is:-
5:35/11
= 5÷35/11
=5×11/35
=11/7
=11:7
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