Physics, asked by hanaa1562, 11 months ago

Body cover a distance of 5 metre along a semicircular path the ratio of distance to displacement is

Answers

Answered by hello6527
4

Answer:

11:7 (Simplest form)

Explanation:

A/Q:-

Circumference of the semi-circle=5m

=>πr = 5m

=>22/7 × r =5m

=>r= 5÷22/7

=>r=5 × 7/22

=>r = 35/22

Distance covered =5m (given)

Therefore, Displacement = r+r

= 2r

=2×35/22

=35/11

The ratio of distance to Displacement is:-

5:35/11

= 5÷35/11

=5×11/35

=11/7

=11:7

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