Question

A well is 14 deep a warm at the bottom of it starts to crowl up. It crawls 5 m in a day and slip 2 m at night on which day it come out of the well

Answer 1

Step-by-step explanation:

one day before to reach to

14-5=9

Resultant crawling per day

5-2=3

In 3 days it reaches 9m

on 4th it reaches top

Answer 2

Answer:

Worm will come out of the well on the 4th day.

Step-by-step explanation:

• Given, distance travelled by worm in crawling=5m
• Distance slipped by worm=2 m
• Net distance travelled is $5-2=3m$
• At the end of 2nd day, distance travelled=$3*2=6m$
• At the end of 3rd-day distance travelled=$3*3=9m$
• On the 4th day, worm crawl 5 m. Thus distance travelled =$9+5=14m$
• Since the worm crawled the total height of the well i.e. 14 m. It will not slip and come out of the well.