Body of mass m accelerates uniformly from rest to v in time t.As function of x instantaneous power delivered to body is
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we have
v = u + at
now, as u = 0 and t = T1
a = v/T1
so, force
F = ma = m(v/T1)
now,
we also have
s = ut + (1/2)at2
as u = 0
s = (1/2)at2 = (1/2) (v/T1).t2
and work done will be
W = F.s = m(v/T1) .(1/2) (v/T1).t2
or
W = (1/2).m.(v/T1)2.t2
and finally the instantaneous power will be
P = W/t = [(1/2).m.(v/T1)2.t2] / t
thus,
P = (1/2).m.(v/T1)2.t
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