Physics, asked by mayank5386, 8 months ago

body of mass m accelerates uniformly from rest to velocity v1 in time interval T1 . the instantaneous power delivered to the body as a funcyion of time it is.

answer should be= mv12 t/T12​

Answers

Answered by Anonymous
11

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Body of mass m accelerates uniformly from rest to velocity v1 in time interval T1 . the instantaneous power delivered to the body as a funcyion of time it is.

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we know that :-

⇒ v = u + at

now , let's take

⇒ u = 0

⇒ t = T1

⇒ a = v÷T1

so, force

⇒ F = ma = m(v÷T1)

⇒ s = ut + (1÷2)at²

⇒since u = 0

⇒∴ s = (1÷2)at² = (1÷2) (v÷T1)×t²

and work done will be

W = F.s = m(v÷T1) ×(1÷2) (v÷T1)×t²

W = (1÷2) m (v÷T1)²×t²

∴ finally the instantaneous power will be====

P = W/t = [(1÷2).m.(v÷T1)²×t²] / t

⇒∴ P = (1÷2).m.(v÷T1)²×t

Answered by Swethapreetha770
0

ANSWER

Let a be the constant acceleration

Using 1st equation of motion

v1=u+aT1

v1=0+aT1

a=T1v1..........(i)

At any instant t, the velocity v of the body

v=0+at

v=T1v1⋅t.........(ii)

∵P=Fv

    P=mav

    P=m(T1v1)(T1v1⋅t)

   P=T12mv12t

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