Question

boiling point of an aqua solution of non volatile solute is 100.15 °C. what is the freezing point of an aqua solution of 3 by dilute in the above solution with an equal volume of water? the values of Kb and Kf for water are 0.512 and 1.86 K /molality.​

Answer 1

Answer:

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As we know,

=      ΔTb  = kb m;               0.15 = 0.512×m

       m=0.292;                  ΔT f  = k f m  ′

       m′  = m/2;                   T1  −T0  =1.86 ×  2 0.29/2  =0.27   degrees C

       T1  =0 − 0.27 = −0.27  ∘degrees C(answer)