Chemistry, asked by tejalmahesh1, 7 months ago

Bond enthalpy of H2, Cl2 and HCI are 434,242 and 431k) mol^-1
respectively. The enthalpy of formation of HCI will be
a.-93kj b. 245kj c.93kj
d. -245kj

Answers

Answered by nehu215

1

Bond enthalpy of H2, Cl2 and HCI are 434,242 and 431k) mol^-1

respectively. The enthalpy of formation of HCI will be -245kj............hope it help u mate

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