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If a charged particle moves through a region of magnetic field pointing in the direction perpendicular to its direction of velocity. Then during its subsequent motion, (1) Its momentum changes but the kinetic energy remains constant (2) Its momentum and kinetic energy both changes. (3) Its momentum and kinetic energy both remains constant. (4) Its kinetic energy changes but the momentum remains constant.
Answers
Answered by
1
it's momentum changes and kinetic energy remains constant as only the direction of velocity changes and not the magnitude....
kinetic energy depends on mass and magnitude of velocity as velocity is constant kinetic energy is constant
momentum is also dependent on mass and velocity
=m*v
so if v is constant momentum will be constant
kinetic energy depends on mass and magnitude of velocity as velocity is constant kinetic energy is constant
momentum is also dependent on mass and velocity
=m*v
so if v is constant momentum will be constant
Usernameisempty:
EXPLAIN WHY
Answered by
0
Hi friend,
The answer is option (3)...
It is because
1.magnetic force does not cause any change in kinetic energy or speed of the particle.
2.F=QVB=MV²/R
OR , QB=MV/R
OR MV=QBR
Q,B,R ARE CHARGE,MAGNETIC FIELD AND RADIUS RESPECTIVELY WHICH SEEMS TO BE CONSTANT
HENCE
MOMENTUM IS ALSO CONSTANT
HENCE THE ANSWER IS option(3)...
Hope this helps you...
Please mark it as brainliest answer...☺☺☺
The answer is option (3)...
It is because
1.magnetic force does not cause any change in kinetic energy or speed of the particle.
2.F=QVB=MV²/R
OR , QB=MV/R
OR MV=QBR
Q,B,R ARE CHARGE,MAGNETIC FIELD AND RADIUS RESPECTIVELY WHICH SEEMS TO BE CONSTANT
HENCE
MOMENTUM IS ALSO CONSTANT
HENCE THE ANSWER IS option(3)...
Hope this helps you...
Please mark it as brainliest answer...☺☺☺
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