Math, asked by edistian, 1 year ago

plz answer question 68 PLZZ answer fast

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Answered by kvnmurty
7
68.   Let us select  n number of non-identical different balls and 8-n number of identical balls to form a total of 8 balls.

  There is only 1 way of selecting 8-n number of identical balls.
  There are  8Cn ways of selecting n balls from 8 different balls. (combinations)

  combinations with 0 of different balls selected = 8C0
  combinations with 1 of different balls = 8C1
  combinations with 2 of different balls (& 6 identical balls) = 8C2
      ::               ::
  
  combinations with 7 of 8 different balls (&1 from identical ball set)= 8C7
 
Total =  8C0 + 8C1 + 8C2 + 8C3 + 8C4 + 8C5 + 8C6 + 8C7 +  8C8 
         = 2^8 = 256

kvnmurty: clik on red heart thanks above pls
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