Question

Boron has two stable isotopes, 10b (19%) and 11b (81%). The atomic mass that should appear for boron in the periodic table is

Answer 1

Hi there ,,

☆ B10 isotop mass sharing is

19×10 ÷ 100 = 1.9 amu

☆ B11 isotop mass sharing is

81×11 ÷ 100 = 8.91 amu

☆ Atomic mass of boron in periodic table is

8.91 + 1.9 = 10.81 amu

☆ Hope the answer is helpful

Have a nice day

Plz mark as brainliest answer if u satisfied