Δ BOX = 5 cm , OX = 3 cm XB =
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Answer:-
XB= 4 cm
By using Pythagoras Theron:-
BO²= OX²+ XB²
5² = 3² + XB²
25 = 9 + XB²
XB² = 25 - 9
XB² = 16
XB² = √16
XB = 4
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