Question

find a quadratic polynomial, whose zeros are -4 & 1 , respectively​

Answer 1

Step-by-step explanation:

(x-(-4))(x-1)

=(x+4)(x-1)

=(x*x-x*1+4*x-4*1)

=x^2-x+4x-4

= x^2+3x-4

Answer 2

Answer:

Step-by-step explanation:

Let alpha=-4

beta=1

alpha+beta=-4+1=-3=-b/a

alphaxbeta=-4x1=-4=c/a

Therefore quadratic polynomial is x^2+3x-4