BP and cp are the bisectors of LB
g LB
and Lc respectively
prove that x=90°+1/2y
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To prove L80 L = 90°-1 LA 2
Proof - In A ABC
LA+ LB + LL = 180° Angle Sum Property
LA + 2LCB0 +2LOCB
LA + 2(LLBO + LOLB) - 180 - LA LA + LLRO+ Locb = 180 2
=) ) LA + LLBO + LOCB = 90°- LA 2 In A BOC, LAngle LCBO + LOCB + LBOC= 180 Angle Sum = 90° - LA + LBOL = 180° property
2
Q8) LBOL 180°- 90° +LA 2
= 90° + LA 2
Hence, proved ナ
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