Math, asked by Anonymous, 1 year ago

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supritnaik100: 25 is the answer
supritnaik100: There are 2 yellow flowers in third equation but in fourth equation there is only one yellow flower
supritnaik100: In second equation there is blue flower of five petals but in fourth equation there is blue flower of four petals
supritnaik100: Keeping all this in mind answer is 25
srikanth2716: 26

Answers

Answered by Anonymous
70

Let the red flower be R

Given,

R + R + R = 60

3R = 60

R = 20

Let the blue flower be B

Given,

R + B + B = 30

20 + 2B = 30

2B = 10

B = 5

Let the Yellow flower be Y.

Given,

B - Y = 3

Y = 5 -3

Y = 2

As per the question,

Y + R + B =

= 2 + 20 + 5

= 20 + 7

= 27

Naah but 27 is not the answer,

Here in 2nd part of pic 5 petals are present where as in last part its 4 petals.

Thus,

5 petels = 5

4 petals = 4

Answer = 2 +20 + 4

= 26

Answer = 26


Anonymous: where
sachinsingh62: hiii
Anonymous: hi
Answered by Anonymous
1

Red = R

Blue = B

Yellow = Y

First condition,

R + R + R = 60

3R = 60

R = 20

Second condition,

R + B + B = 30

20 + 2B = 30

2B = 10

B = 5

Third Condition,

B - Y = 3

5 - Y = 3

Y = 2

Fourth Condition,

Y + R + B = ?

2 + 20 + 5 = 27

Yellow + Red + Blue = 27


sachinsingh62: hiii
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