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Secondary School Math 5 points
The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102, 152. What is the average of the extracted scores that are extreme values (outliers)?

Answer 1

The average of the extracted scores that are extreme values is 102

Step-by-step explanation:

Given average mark of candidate (Mean) = 128.5

Standard Deviation = 8.2

As per mean and standard deviation method, the extreme values (outliers) are beyond the range

Mean ± 3 × Standard Deviation

This range will be

128.5 - 3 × 8.2 to 128.5 + 3 × 8.2

= 103.9 to 153.1

The three scores extracted are 148, 102, 152

Out of these three scores only 102 is beyond the range above

Therefore, only 102 is the outlier

The average will be 102 only.

Hope this answer is helpful.

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