Question

bus starting from rest moves with a uniform acceleration of 0.1 ms from 2 minutes find the speed Quad the distant Traveller

Answer 1

Given,
Initial velocity(u)="0m/s"
Accelaration(a)="0,1m/s-2"
Time="2 mins=60*2=120 secs"
Final velocity=?

v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e Final Velocity="12m/s"
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)s=144=0.2s=1440=2
s=720m 

Therefore,
(a)=12m/s
(b)=720m


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Answer 2

Answer:

Time– 2min=120s

Velocity– 0

Acceleration–0.1ms-²

A.

V=0+0.1ms-²×120s

V=0+0.1ms-²+¹

V=12ms

B.

S=ut+½at2

S=0×120+½×0.1×(120)×2

S=720m