Math, asked by mantunsingh1977sumit, 9 months ago

by
16). In a fraction, twice the numerator is 2 more than
the denominator. If 3 is added to the numerator

and to the denominator, the new fraction is 2/3
Find the original fraction.​

Answers

Answered by Anonymous
5

Answer:

\large\bold\red{\frac{7}{12}}

Step-by-step explanation:

Let the required fraction be \large{\frac{x}{y}}

Where,

  • Numerator = x
  • Denominator = y

Now,

According to question,

Twice the Numerator is 2 more than Denominator.

Therefore,

We get,

 =  > 2x = y + 2  \\  \\  =  > y = 2x - 2\:  \:  \:  \: .........(1)

Also,

If 3 is added to the Numerator and to the Denominator , the fraction becomes 2/3.

Therefore,

We get,

 =  >  \frac{x + 3}{y + 3}  =  \frac{2}{3}

Substituting the value of y from (1),

We get,

 =  >  \frac{x + 3}{2x - 2 + 3}  =  \frac{2}{3}  \\  \\  =  > 3( x + 3) = 2(2x  + 1) \\  \\  =  > 3x + 9 = 4x  +  2 \\  \\  =  > 4x - 3x = 9  - 2 \\  \\  =  >  x = 7

Therefore,

We get,

 =  > y = 2 \times 7 - 2 \\  \\  =  > y = 14- 2 \\  \\  =  > y = 12

Hence,

The required fraction is \large\bold{\frac{7}{12}}

Answered by AnIntrovert
0

Correct Question :

In a fraction, twice the numerator is 2 more than the denominator. If 3 is added to the numerator and to the denominator, the new fraction is 2/3 . Find the original fraction.

Given :

In a fraction, twice the numerator is 2 more than the denominator.

If 3 is added to the numerator and to the denominator, the new fraction is 2/3.

To find :

The original fraction.

Solution :

Let the numerator be x and the denominator be y .

According to the 1st condition :-

In a fraction, twice the numerator is 2 more than the denominator.

\implies\sf{2x=y+2}

\implies\sf{y=2x-2........eq(1)}

According to 2nd condition :-

If 3 is added to the numerator and to the denominator, the new fraction is 2/3.

\implies\sf{\frac{x+3}{y+3}=\frac{2}{3}}

\implies\sf{3x+9=2y+6}

✪ Now put the value of y=2x-2 from eq (1)✪

\implies\sf{3x+9=2(2x-2)+6}

\implies\sf{3x+9=4x-4+6}

\implies\sf{3x-4x=-9+2}

\implies\sf{-x=-7}

\implies\sf{x=7}

✪ Now put x = 7 in eq(1) ✪

\implies\sf{y=2x-2}

\implies\sf{y=2\times\:7-2}

\implies\sf{y=14-2}

\implies\sf{y=12}

★ Numerator = 7

★ Denominator = 12

{\boxed{\bold{Fraction=\dfrac{Numerator}{Denominator}}}}

Therefore,

{\boxed{\purple{\bold{Original\: fraction=\dfrac{x}{y}=\dfrac{7}{12}}}}}</p><p>

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