Question

by him.
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11. A man gave 25% of the amount of money with him to his eldest son, 20% to his
younger son and 20% of the remainder to his daughter and the rest 880 to his
Find the amount of money he had with him and also find the ratio of the mone
received by his eldest son to his younger son and to his daughter. how to come 1000
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Answer 1

Correct Question

A man gave 25% of the amount of money with him to his eldest son, 20% to his younger son and 20% of the remainder to his daughter and the rest 880 to his wife. Find the amount of money he had with him and also find the ratio of the money received by his eldest son, his younger son and to his daughter?

Answer:

To Find:-

The amount of money he had with him

Ratio of the money received

Solution:

Let the amount of money he had be Rs. x.

step-by-step explanation:

Amount of money he gave to his eldest son

= 25% of Rs. x

= 25/100 of Rs. x

= Rs. x/4

Amount of money he gave to his younger son

= 20% of Rs. x

= 20/100 of Rs. x

= Rs. x/5

Amount of money left

= Rs. {x-(x/4)-(x/5)}

= Rs. 11/20x

Amount of money he gave to his daughter

= 20% of Rs. 11/20x

$= \dfrac{20}{100} \times \dfrac{11}{20}x$

= Rs. 11x/100

Given, the amount of money left was given by him to his wife = Rs. 880

Amount of money left was given by him to his wife=Rs. 880

⟹ 11x/25 = 880

$\implies \: \dfrac{880 \times 25}{11}$

⟹ x = 2000

Therefore, the amount of money he had with him is Rs. 2000

The amount of money received by his eldest son

$= \dfrac{2000}{4}$

= Rs. 500

The amount of money received by his younger son

$= \dfrac{2000}{5}$

= Rs. 400

The amount of money he gave to his daughter

$= \dfrac{11}{100} \times 2000$

= Rs. 220

• The ratio of the money received by his eldest son, younger son and daughter

= 500 : 400 : 220

= 25 : 20 : 11