Math, asked by anirudhrnd3241, 1 year ago

by how much does 3x²-5x²+2x-3 exceeds 2x³-3x²+x+1

Answers

Answered by mysticd
20
here u typed mistake 3x^2 i think it is 3x^3
let 3x^3-5x^2+2x-3 exceeds 2x^3-3x^2+x+1 by 'd'
d=(3x^3-5x^2+2x-3)-(2x^3-3x^2+x+1)
=3x^3-5x^2+2x-3-2x^3+3x^2-x-1
=x^3-2x^2+x-4
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