Question

By how much is the sum of 4 and 5 more than the differenc of 4 and 5

Answer 1

sum is 10 more than the difference

Answer 2

Answer:

Required answer is 8.

Step-by-step explanation:

Given sum of 4 and 5 and difference of 4 and 5.

Now sum of 4 and 5 $(4 + 5) = 9$

and difference of 4 and 5 $(5 - 4) = 1$

Here we want to find by how much is the sum of 4 and 5 more than the difference of 4 and 5 ?

Required answer

$= (4 + 5) - (5 - 4) \\ = 9 - 1 \\ = 8$

This is a problem of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Two important Mathematics problems:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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