Question

by-product is obtained.
25. The image of an object formed by a mirror is real, inverted and is of magnification --1. If the image is
at the distance of 30 cmn from the mirror, where is the object placed? Find the position of the image if
the object is now moved 20 cm towards the mirror. What is the nature of the image obtained? Justify
your answer with the help of ray diagram​

Answer 1

Answer:

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Explanation:

fhfhrhrthrbjrjrjjeh37 gt b4Ix8xuhevr hu 8g73bb bh fug7cu3g vg uFitfN intellectual niya

ggghdjur

Answer 2

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.