Question

by trying two coins what is the probability of getting head and tail??​

Answer 1

Answer:

Let E6 = event of getting at least 1 head. Then,

E6 = {HT, TH, HH} and, therefore, n(E6) = 3.

Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.

Answer 2

Answer:

Step-by-step explanation:

1/2 because if we are tossing two coins there will chances of 2 heads and 2 tails

Probability=no.of outcomes/total outcomes

Probability of head =2/4=1/2

Probability of tails =2/4=1/2

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