Question

by using substituting method solve s-y=3 and s/3 + t/2=6

Answer 1

Hi...☺

Here is your answer...✌

Given equation :

s - t = 3 -----(1)

s/3 + t/2 = 6 -----(2)

From (1) , we have

s - t = 3

s = 3 + t -----(3)

Putting value of s in (2) , we get

(3+t)/3 + t/2 = 6

( 2(3+t) + 3t ) / 6 = 6

6 + 2t + 3t = 6×6

5t = 36-6

5t = 30

=> t = 6

Putting t = 6 in (3), we get

s = 3 + 6 = 9

Thus
s = 9 , t = 6

Answer 2

Hii friend..... ☺

S-T = 3.........(1)

S/3 + T/2 = 6

2S + 3T/6 = 6

2S+3T = 36..…....(2)

From equation (1) we get,

S - T = 3

S = 3+T........(3)

Putting the value of S in equation (2)

2S +3T = 36

2 × (3+T) +3T = 36

6 + 2T +3T = 36

5T = 36-6

5T = 30

T = 30/5 = 6.

Putting the value of T in equation (3)

S = 3+T => 3+6 = 9

Hence,

S = 9 and T = 6.

HOPE IT WILL HELP YOU....... ☺