By using sum of infinite geometric progression solve 1/1^2 + 1/2^2 + 1/4^2 + 1/8^2 + ............
Answers
Answered by
5
Given,
1/1^2 + 1/2^2 + 1/4^2 + 1/8^2 + ............
→1/1^2 + 1/2² + 1/2⁴ + 1/2^6+ ............
Observing we get . common ration of terms r= 1/2²
and first term a= 1
We know that
sum of infinite terms of GP is = a/(1-r)
→ 1/(1 - 1/2²)
→1/ (1- 1/4)
→4/3 ans.
See picture!
Hope it helped you!
1/1^2 + 1/2^2 + 1/4^2 + 1/8^2 + ............
→1/1^2 + 1/2² + 1/2⁴ + 1/2^6+ ............
Observing we get . common ration of terms r= 1/2²
and first term a= 1
We know that
sum of infinite terms of GP is = a/(1-r)
→ 1/(1 - 1/2²)
→1/ (1- 1/4)
→4/3 ans.
See picture!
Hope it helped you!
Attachments:
Similar questions