Question

If 1.5 moles of oxygen combine with Al to form Al2O3,the mass of Al in g used in the reaction is

Answer 1

4 Al + 302 -----> 2alo3

Mass of 4 aluminium is 108 g
So 3 moles of oxygen react with 1o8g of al
So 1 moles of oxygen react with 108 ÷ 3 g of al
And 1.5 moles of oxygen react with 108 × 1.5 ÷ 3 g of al
Al = 54 gram



Hope it helps

Answer 2

Answer:

The mass of Al used in the reaction is 54g.

Explanation:

The reaction will proceed as follows,

$2Al+1.5O_2\rightarrow Al_2O_3$     (1)

Where,

Al=Aluminum

O₂=Oxygen

Al₂O₃=Aluminum Oxide

From reaction (1) we can see that 1.5 moles of oxygen react with 2 moles of Aluminium.

The molar mass of Aluminum(Al)=27g

So, the mass of Aluminium used in the reaction is=27g×2=54g

Hence, the mass of Al used in the reaction is 54g.

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