By walking at 3/4 of his usual speed, a man reaches his office 20 minutes later than usual. His usual time is
Answers
Question :-- By walking at 3/4 of his usual speed, a man reaches his office 20 minutes later than usual. His usual time is ?
Solution :---
Let s = his usual speed
t = his usual time
we know that now, distance = speed * Time .
Then ,,
D = (3/4)s * (t+20)
Since the distance is the same we can equate this to his regular day which is D = s*t
Equating both now, we get,
→ s*t = (3/4)s * (t+20)
→ st = 3st/4 + 15s
→ st - 3st/4 = 15s
→ st/4 = 15s
( s will cancel from both sides)
→ t = 15*4 = 60 minutes .
Hence, his usual time is 60 minutes or 1 hour .
Answer:
Time Taken by Man Usually is 1 Hour or 60 mins
Step-by-step explanation:
We Have :-
Man is walking at 3/4 of his usual speed
Reaches 20 mins late
To find :-
Usual time
Formula Used :-
Distance = Speed * Time
Solution :-
Let the usual speed be a km/h
Let the usual time be b hours
Distance = ab km
New speed = 3a/4 km/h
New time = b + 20/60 hours
= b + 1/3 hours
Distance = 3a/4 ( b + 1/3 ) km
Equating Distance
ab = 3a/4 ( b + 1/3 )
4ab = 3ab + a
ab - a = 0
a ( b - 1 ) = 0
a = 0 ( which is not possible ) , b = 1 hour
Time Take by Man usually is 1 hour or 60 mins