Calculate the number of lone pair on the central atom in if5 and xef2 and predict the shape on the basis of vsepr theory
Answers
Answer:
XeF2 is an abbreviation for the chemical compound Xenon Difluoride. It is a powerful fluorinating as well as an oxidizing agent. Apart from XeF2, there are other Xenon compounds such as XeF4 ( Xenon Tetrafluoride) and XeF6 ( Xenon Hexafluoride). Out of these compounds, XeF2 is the most stable one. It is a white
crystalline solid used for fluorinating purposes in electrochemical procedures and laboratories. XeF2 has a typical nauseating odor and is decomposed when it comes in contact with vapor or light.
The number of lone pair on the central atom in if5 is 1 and in xef2 is 3 and the shape on the basis of vsepr theory for IF₅ is square pyramidal and for XeF₂ is linear
* For IF₅
- central atom in IF₅ is iodine
- there are 7 electrons in the valence shell of iodine
- out of these, 5 electrons forms bonds with 5 fluorine atoms by sharing
- so only 2 electrons are left unpaired
- hence there are 5 bond pairs and only 1 lone pair of electrons in IF₅
- by VSEPR theory, IF₅ has octahedral arrangement of electron pairs
- the only lone pair occupies an axial position
- hence the shape of IF₅ is square pyramidal
* For XeF₂
- central atom in XeF₂ is Xenon
- there are 8 electrons in the valence shell of xenon
- out of these, 2 electrons forms bonds with 2 fluorine atoms by sharing of electrons
- so 6 electrons are left unpaired
- hence there are 2 bond pairs and 3 lone pair of electrons in XeF₂
- hence, by VSEPR theory, XeF₂ has trigonal bipyramidal arrangement of electron pairs
- these must attain such positions to minimise the repulsions
-so the 3 lone pairs occupy the equatorial positions and the 2 bond pairs occupy the axial positions
- Hence the shape of XeF₂ becomes linear