By what least no. should 1536 be divided to get a perfect cube also find the cube root of the number obtained
Answers
Answered by
47
❤❤❤hay.....❤❤❤
plzz... mark it as brainlist
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it is your answer ....
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here it is given......
no .. is 1536
so.....
prime factorisation of 1536
=2×2×2×2×2×2×2×2×2×3
=8×8×8×3=512×3
here we see..
512 is prefect cube
so.....
if 1536 is devided by.. 3
then we get a prefect cube
so.... the lowest no.. is
3 answer..
--------------------------------------
qube root of new no.. 512 is 8
➖➖➖➖➖➖➖➖➖➖➖
plzz... mark it as brainlist
✔✔✔✔✔✔✔✔✔
it is your answer ....
⚓⚓⚓⚓⚓⚓⚓⚓
here it is given......
no .. is 1536
so.....
prime factorisation of 1536
=2×2×2×2×2×2×2×2×2×3
=8×8×8×3=512×3
here we see..
512 is prefect cube
so.....
if 1536 is devided by.. 3
then we get a prefect cube
so.... the lowest no.. is
3 answer..
--------------------------------------
qube root of new no.. 512 is 8
➖➖➖➖➖➖➖➖➖➖➖
Answered by
37
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Find the prime factors of 1536:
1536 = 2⁹ x 3
.
Find k:
A number is a perfect cube if the exponent is a multiple of 3.
Let k be the number.
1536 = 2⁹ x 3
1536/k = 2⁹
k = 3
.
Find the new number:
1536/k = 1536/3 = 512
.
Find the cube root of the number:
∛512 = 8
.
Answer: The cube root of the new number is 8
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