Math, asked by THEGUY1408, 1 year ago

By what least no. should 1536 be divided to get a perfect cube also find the cube root of the number obtained

Answers

Answered by mourfiousamanraj
47
❤❤❤hay.....❤❤❤
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it is your answer ....
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here it is given......
no .. is 1536
so.....
prime factorisation of 1536
=2×2×2×2×2×2×2×2×2×3
=8×8×8×3=512×3
here we see..
512 is prefect cube
so.....
if 1536 is devided by.. 3
then we get a prefect cube
so.... the lowest no.. is
3 answer..
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qube root of new no.. 512 is 8
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Answered by TooFree
37

 \textbf {Hey there, here is the solution.}

.............................................................................................

Find the prime factors of 1536:

1536 = 2⁹ x 3

.

Find k:

A number is a perfect cube if the exponent is a multiple of 3.

Let k be the number.

1536 = 2⁹ x 3

1536/k = 2⁹

k = 3

.

Find the new number:

1536/k = 1536/3 = 512

.

Find the cube root of the number:

∛512 = 8

.

Answer: The cube root of the new number is 8


 \textbf {Cheers }


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