Question

by what smallest no should 6912 be divided to get a perfect cube

Answer 1

The factors of

6912 = 2x2x2x2x2x2x2x2x3x3x3 = 2^8x3^3

So divide 6912 by 4, the smallest number, to get 1728 which is a cube of 12.

Answer is 4.

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