by which least number 250 × 512 should be divided to make it a perfect cube
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Answered by
64
×
,
250 = 2×5×5×5
=> 250 = (2) × (5)^3
So 250 is not a perfect cube.
,
512 = 2×2×2×2×2×2×2×2×2
=> 512 = (2)^3 × (2)^3 × (2)^3
So 512 is a perfect cube.
,
× = (2) × (5)^3 × (2)^3 × (2)^3 × (2)^3
If digit 2 is divided from the term,then it will be a perfect cube all together.
by which × to .
Answered by
18
\textbf{The given number is,}The given number is,
\textbf{250}250 × \textbf{512}512
\textbf{Lets resolve 250 in prime factors}Lets resolve 250 in prime factors ,
250 = 2×5×5×5
=> 250 = (2) × (5)^3
So 250 is not a perfect cube.
\textbf{Lets resolve 512 in prime factors}Lets resolve 512 in prime factors ,
512 = 2×2×2×2×2×2×2×2×2
=> 512 = (2)^3 × (2)^3 × (2)^3
So 512 is a perfect cube.
\textbf{Lets comeback to the question}Lets comeback to the question ,
\textbf{250}250 ×\textbf{512}512 = (2) × (5)^3 × (2)^3 × (2)^3 × (2)^3
\textbf{We can clearly see that,}We can clearly see that,
If digit 2 is divided from the term,then it will be a perfect cube all together.
\textbf{The least number}The least number by which \textbf{250}250 ×\textbf{512}512 \textbf{should be divided}should be divided to \textbf{make it perfect cube is 3}make it perfect cube is 3 .
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