Question

c) An organic compound ‘p’ containing Carbon, Hydrogen and oxygen only contains 1.92 g of

carbon, 0.48 g of Hydrogen. If the compounds weighs 3.68 g and has a vapour density of 69.

Find the molecular formula

[ c = 12, H = 1, 0 = 16 ]​

Answer 1

Explanation:

0.92 g of an organic compound containing carbon, hydrogen and oxygen was analysed by combustion method. The increase in the mass of the U - tube and

Answer 2

C 1.92 12 0.16 2
H 0.48 1 0.48 6
O 1.28 16 0.08 1
Thus on solving, EF=C2H6O
EFW= 2x12 + 6x1 + 16 = 24+6+16 = 46
MFW = VDx2 = 69x2 = 138
n = MFW/EFW = 138/46 = 3
Therefore, MF = (EF)3
= (C2H6O)3
= (C6H18O3)