(C) PT is a tangent and PAB is a secant to a circle. Prove that PT2= PA X PB.
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See the explanation
Step-by-step explanation:
In ΔPBT & ΔPTA
∠P = ∠P [Common]
∠T = ∠B [Alternate segment theorem]
⇒ ΔPBT similar to ΔPTA by AA criteria
PT/PA = PB/PT [CPST]
⇒ PT² = PA*PB
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