Math, asked by kanishkamandal2003, 11 months ago

(C) PT is a tangent and PAB is a secant to a circle. Prove that PT2= PA X PB.

Answers

Answered by achubadyal4

4

Answer:

See the explanation

Step-by-step explanation:

In ΔPBT & ΔPTA

∠P = ∠P [Common]

∠T = ∠B [Alternate segment theorem]

⇒ ΔPBT similar to ΔPTA by AA criteria

PT/PA = PB/PT [CPST]

⇒ PT² = PA*PB

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