C. Write the first four terms of the sequence whose nth term is given by the rule. Show your Solution.
1. an = 2n-1
3. an = 3n
5. an = 8 - 2n
2. an = 12-3n
5n + 5
4. an = 5n + 5
5. an = 8 - 2n
Answers
Answer:
give 1,2,3,4 to each equation to get answer
Answer:
1. i) an = 2n - 1
a1 = 2 (1) - 1
a1 = 2 - 1
= 1
ii) an = 2n - 1
a2 = 2 (2) - 1
a2 = 4 -1
= 3
iii) an = 2n - 1
a3 = 2 (3) - 1
a3 = 6 - 1
a3 = 5
iv) an = 2n - 1
a4 = 2(4) - 1
= 8 - 1
= 7
{1,3,5,7,...}
2. an = 12 - 3n
a1 = 12 - 3 (1)
= 12 -3
= 9
a2 = 12 - 3(2)
= 12 - 6
= 6
a3 = 12 - 3(3)
= 12 -9
= 3
a4 = 12 - 3(4)
= 12 - 12
= 0
{9, 6, 3,0, ...}
3. i) an = 3n
a1 = 3 (1)
a1 = 3
ii) a2 = 3 (2)
a2 = 6
iii) a3 = 3(3)
= 9
iv) a4 = 3 (4)
= 12
{3, 6, 9, 12...}
4. an = 5n + 5
i) a1 = 5(1) + 5
= 5 +5
= 10
ii) a2 = 5(2) + 5
= 10 +5
= 15
iii) a3 = 5(3) + 5
= 15 +5
= 20
iv) a4 = 5 (4) + 5
= 20 + 5
= 25
{10, 15, 20, 25, ...}
5. an = 8 - 2n
i) a1 = 8 - 2 (1)
= 8 - 2
= 6
ii) a2 = 8 - 2 (2)
= 8 - 4
= 4
iii) a3 = 8 - 2 (3)
= 8 - 6
= 2
iv) a4 = 8 - 2 (4)
= 8 - 8
= 0
{6, 4, 2, 0, ...}
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