Question

C3h8+5o2=3co2+4h20 find ∆ng

Answer 1

Answer:

$\displaystyle \sf \longrightarrow \Delta \ n_g=-3$

Explanation:

Given :

$\displaystyle \sf C_3H_8+5 \ O_2( g) \rightleftharpoons 3 \ CO_2 (g)+ 4 \ H_2O(l)$

We are asked to find value of Δ n g :

Since we know Δ n g is difference of sum of product moles and sum of reactant moles of gases. We will not consider liquid one!

$\displaystyle \sf \longrightarrow \Delta \ n_g=(3)-(1+5)$

$\displaystyle \sf \longrightarrow \Delta \ n_g=3-6$

$\displaystyle \sf \longrightarrow \Delta \ n_g=-3$

Therefore we get required answer.

Read more :

Give the relation between K_p and K_c for the for the reaction 2 NaCl ( g ) ⇄ 2 Na ( g ) + Cl₂ ( g ).

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